Fast Factorial Algorithms

 (luschny.de)

46 points | by nill0 3 days ago

8 comments

  • ipeev 8 hours ago
    A cached map will do best if you actualy need a fast factorial. There are very little entries before the numbers become pointlessly big.
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    • karmakurtisaani 3 hours ago
      Not if you want to calculate modulo some big number. Might still be useful tho.
  • FiatLuxDave 3 hours ago
    I know it's not technically a fast factorial algorithm, but I'm kinda surprised that there is no mention on the site of the AKS primality test (https://en.wikipedia.org/wiki/AKS_primality_test). It's operation is sort of like an FFT for canceling out factorials mod N.
  • smokel 10 hours ago
    I hoped this would help me solve some more Project Euler [1] problems. Unfortunately, the algorithms given are not explained in detail, so the learning experience is somewhat mediocre. Then again, I have ChatGPT to elucidate them for me.

    This article [2] has some interesting details on the swinging factorial function n≀, but I can't seem to find the essay that it references: "Swing, divide and conquer the factorial", 2008.

    [1] https://projecteuler.net/

    [2] https://oeis.org/A000142/a000142.pdf

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    • nyankosensei 3 hours ago
      The OP includes a link to an English excerpt written by the author of the "Swing, divide and conquer the factorial" manuscript:

      http://www.luschny.de/math/factorial/SwingIntro.pdf

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    • mjevans 6 hours ago
      My approach to the first 100 Euler eventually involved a bitmap of possible primes (only odd numbers, there's only one even prime) which was initially seeded by a 'magic number' set representing the lowest primes and would grow up to a target number of cached small / really fast primes.

      Then the algorithms I understand less kick in. Most of those involve some form of modo math to wrap the number space based on one or more origami like folds and use well known and test algorithms which were previously exhaustively proven to cover the entire 32 bit number-space when utilized in a composite fashion.

  • zamadatix 9 hours ago
    To all commenting about the Sitrling formula, there is a separate page linked at the end for approximations http://www.luschny.de/math/factorial/approx/SimpleCases.html which contains many advanced options to compare for that.
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    • imglorp 5 hours ago
      I've always wondered if Stirling(n) can be used to arrive quickly in the vicinity of n!, and then use a search of some kind to get to the exact target.
  • looneysquash 6 hours ago
    I wonder if any compiler can rewrite that last one into one of the others.
  • anthk 3 hours ago
    Zenlisp:

    If it runs fast there, it will run fast everywhere, as integers are made of Lisp conses on purpose, so you can see Lisp built from itself as if they were Peano axioms:

    https://www.t3x.org/zsp/

      (require 'nmath)
  (gc)
  (define (fac n)
   (fi '#1  n))
  
  (define  (fi a n)
   (or  
   (and (= n '#0) 1) 
   (and (= n '#1) a)
    (and 
    (fi
     (* a n)
     (- n '#1)
      ))))
  
  
  (fac '#10)
  (fac '#0)
    Test:

        -:cat fact.l | ./zl
     zenlisp 2013-11-22 by Nils M Holm
     => :t
     => '(#125434 #5638)
     => 'fac
     => 'fi
     => '#3628800
     => '1
    Test with (trace fi) before running (fac 0) and (fac 10)

        zenlisp 2013-11-22 by Nils M Holm
    => :t
    => '(#125434 #5638)
    => 'fac
    => 'fi
    => :t
    + (fi #1 #10)
    + (fi #10 #9)
    + (fi #90 #8)
    + (fi #720 #7)
    + (fi #5040 #6)
    + (fi #30240 #5)
    + (fi #151200 #4)
    + (fi #604800 #3)
    + (fi #1814400 #2)
    + (fi #3628800 #1)
    => '#3628800
    + (fi #1 #0)
    => '1
    Here you can see how (fi) works on every iteration.

    Integers are not actual integers, but lists.

    '#3628800 it's '(3 6 2 8 8 0 0).

    Open "nmath.l" to see how are digits implemented. Base.t it's interesting too, as it explains you some functions.

  • dvh 9 hours ago
    No Stirling formula?
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